Cause and Effect Paper for School

In the past three months Ruth Disselkoen, has cut her breaks short to complete her work, complains of being tired, and twice a month requires overtime hours, which causes the company an additional $200. 00 a month; on the other hand, Frank Daley, has complained about the her poor work quality. Whereas, Jack Snyder seems to have little work to do, he arrive late twice a week, he takes extra breaks; although his work is always professionally completed. Even though, nothing has changed in their personal lives.I would like to have interpersonal meeting with both Jack Snyder, and Ruth Disselkoen to investigate the root of the problem, so I can determine my next course of action, and if I have the authority to implement any of the changes necessary that will eventually stop costing the company and extra $200. 00 monthly. Since Jessica Hilo’s is out on a Leave of Absence and her work assignments have been split up amongst Jack and Ruth. Jessica Hilo is one of Jack Snyder’s bos ses so; it is only fair that Jack is responsible for Jessica Hilo’s work load, and not Ruth Disselkoen.I have noticed that this entire problem began three months ago when Jessica Hilo’s took a Leave of absence and some of her work load was reassigned to Ruth Disselkoen. I believe that Jessica Hilo’s, work is causing Ruth to cut her breaks short and work overtime twice a month. Therefore, I will discuss this with the Human Resources Director, Liz, Jakowski, and I will present the idea of giving Jessica Hilo’s, entire work load to Jack Snyder, and this course of action will eliminate the monetary expenditure of $200. 00 that the company is paying monthly for overtime. I will wait for Liz Jakowski, response to determine my next course of action.

Transfer Functions

ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ TRANSFER FUNCTIONS AND BLOCK DIAGRAMS 1. Introduction 2. Transfer Function of Linear Time-Invariant (LTI) Systems 3. Block Diagrams 4. Multiple Inputs 5. Transfer Functions with MATLAB 6. Time Response Analysis with MATLAB 1. Introduction An important step in the analysis and design of control systems is the mathematical modelling of the controlled process. There are a number of mathematical representations to describe a controlled process:Differential equations: You have learned this before. Transfer function: It is defined as the ratio of the Laplace transform of the output variable to the Laplace transform of the input variable, with all zero initial conditions. Block diagram: It is used to represent all types of systems. It can be used, together with transfer functions, to describe the cause and effect relationships throughout the system. State-space-representation: You will study this in an advanced Control Systems Design course. 1. 1. Linear Time-Variant and Linear Time-Invariant SystemsDefinition 1: A time-variable differential equation is a differential equation with one or more of its coefficients are functions of time, t. For example, the differential equation: d 2 y( t ) t2 + y( t ) = u ( t ) dt 2 (where u and y are dependent variables) is time-variable since the term t2d2y/dt2 depends explicitly on t through the coefficient t2. An example of a time-varying system is a spacecraft system which the mass of spacecraft changes during flight due to fuel consumption. Definition 2: A time-invariant differential equation is a differential equation in which none of its coefficients depend on the independent time variable, t.For example, the differential equation: d 2 y( t ) dy( t ) m +b + y( t ) = u ( t ) 2 dt dt where the coefficients m and b are constants, is time-invariant since the equation depends only implicitly on t through the dependent variables y and u and their derivatives. 1 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ Dynamic systems that are described by linear, constant-coefficient, differential equations are called linear time-invariant (LTI) systems. 2. Transfer Function of Linear Time-Invariant (LTI) SystemsThe transfer function of a linear, time-invariant system is defined as the ratio of the Laplace (driving function) U(s) = transform of the output (response function), Y(s) = {y(t)}, to the Laplace transform of the input {u(t)}, under the assumption that all initial conditions are zero. u(t) System differential equation y(t) Taking the Laplace transform with zero initial conditions, U(s) Transfer function: System transfer function G (s) = Y(s) Y(s) U(s) A dynamic system can be described by the following time-invariant differential equation: an d n y( t ) d n ? 1 y( t ) dy( t ) + a n ? 1 + L + a1 + a 0 y( t ) n ? 1 dt dt dt d m u(t) d m ? 1 u ( t ) du ( t ) = bm + b m ? 1 + L + b1 + b 0 u(t) m m ? 1 dt dt dt Taking the Laplace transform and considering zero initial conditions we have: (a n ) ( ) s n + a n ? 1s n ? 1 + L + a 1s + a 0 Y(s) = b m s m + b m ? 1s m ? 1 + L + b1s + b 0 U(s) The transfer function between u(t) and y(t) is given by: Y(s) b m s m + b m ? 1s m ? 1 + L + b1s + b 0 M (s) = = G (s) = U(s) N(s) a n s n + a n ? 1s n ? 1 + L + a 1s + a 0 where G(s) = M(s)/N(s) is the transfer function of the system; the roots of N(s) are called poles of the system and the roots of M(s) are called zeros of the system.By setting the denominator function to zero, we obtain what is referred to as the characteristic equation: ansn + an-1sn-1 + + a1s + a0 = 0 We shall see later that the stability of linear, SISO systems is completely governed by the roots of the characteristic equation. 2 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ______________ __________________________________________________________________ A transfer function has the following properties: †¢ The transfer function is defined only for a linear time-invariant system. It is not defined for nonlinear systems. The transfer function between a pair of input and output variables is the ratio of the Laplace transform of the output to the Laplace transform of the input. †¢ All initial conditions of the system are set to zero. †¢ The transfer function is independent of the input of the system. To derive the transfer function of a system, we use the following procedures: 1. Develop the differential equation for the system by using the physical laws, e. g. Newton’s laws and Kirchhoff’s laws. 2. Take the Laplace transform of the differential equation under the zero initial conditions. 3.Take the ratio of the output Y(s) to the input U(s). This ratio is the transfer function. Example: Consider the following RC circuit. 1) Find the transfer function of the network, Vo(s)/Vi(s). 2) Find the response vo(t) for a unit-step input, i. e. ?0 t < 0 v i (t) = ? ?1 t ? 0 Solution: 3 R vi(t) C vo(t) ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ Exercise: Consider the LCR electrical network shown in the figure below. Find the transfer function G(s) = Vo(s)/Vi(s). L R i(t) vi(t) vo(t) CExercise: Find the time response of vo(t) of the above system for R = 2. 5? , C = 0. 5F, L=0. 5H and ? 0 t < 0 . v i (t) = ? ?2 t ? 0 4 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ Exercise: In the mechanical system shown in the figure, m is the mass, k is the spring constant, b is the friction constant, u(t) is an external applied force and y(t) is the resulting displacement. y(t) k m u(t) b 1) Find the differential equation of the system 2) Find the trans fer function between the input U(s) and the output Y(s). 5ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ 3. Block Diagrams A block diagram of a system is a pictorial representation of the functions performed by each component and of the flow of signals. The block diagram gives an overview of the system. Block diagram items: Summing point Takeoff point Block Transfer function +_ The above figure shows the way the various items in block diagrams are represented. Arrows are used to represent the directions of signal flow. A summing point is where signals are algebraically added together.The takeoff point is similar to the electrical circuit takeoff point. The block is usually drawn with its transfer funciton written inside it. We will use the following terminology for block diagrams throughout this course: R(s) = reference input (command) Y(s) = output (controlled variable) U(s) = input (act uating signal) E(s) = error signal F(s) = feedback signal G(s) = forward path transfer function H(s) = feedback transfer fucntion R(s) Y(s) E(s) G(s) +_ F(s) H(s) Single block: U(s) Y(s) Y(s) = G(s)U(s) G(s) U(s) is the input to the block, Y(s) is the output of the block and G(s) is the transfer function of the block.Series connection: U(s) X(s) G1(s) Y(s) G2(s) 6 Y(s) = G1(s)G2(s)U(s) ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ Parallel connection (feed forward): G1(s) + U(s) Y(s) Y(s) = [G1(s) + G2(s)]U(s) + G2(s) Negative feedback system (closed-loop system): R(s) E(s) +_ The closed loop transfer function: Y(s) G(s) Y(s) G(s) = R(s) 1 + G(s) Exercise: Find the closed-loop transfer function for the following block diagram: R(s) Y(s) E(s) G(s) +_ F(s) H(s) 7 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) __________________________________________________________________ _____________ Exercise: A control system has a forward path of two elements with transfer functions K and 1/(s+1) as shown. If the feedback path has a transfer function s, what is the transfer function of the closed loop system. R(s) +_ Y(s) 1 s +1 K s Moving a summing point ahead of a block: R(s) Y(s) G(s) + R(s) Y(s) +  ± G(s)  ± F(s) 1/G(s) F(s) Y(s) = G(s)R(s)  ± F(s) Moving a summing point beyond a block: R(s) Y(s) + R(s) G(s) Y(s) G(s)  ± +  ± F(s) G(s) F(s) Y(s) = G(s)[R(s)  ± F(s)] Moving a takeoff point ahead of a block: R(s) Y(s) R(s) Y(s) G(s) G(s) Y(s)Y(s) G(s) Y(s) = G(s)R(s) 8 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ Moving a takeoff point beyond a block: R(s) Y(s) R(s) Y(s) G(s) G(s) R(s) R(s) 1/G(s) Y(s) = G(s)R(s) Moving a takeoff point ahead of a summing point: R(s) Y(s) + Y(s)  ± F(s) R(s)  ± F(s) +  ± Y(s) + Y(s) Y(s) = R(s)  ± F(s) Moving a t akeoff point beyond a summing point: R(s) R(s) Y(s) + Y(s) +  ±  ± F(s)  ± R(s) F(s) R(s) + Y(s) = R(s)  ± F(s) Exercise: Reduce the following block diagram and determine the transfer function. R(s) + _ + G1(s) G2(s) G3(s) _ Y(s) + + H1(s)G4(s) H2(s) 9 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ Exercise: Reduce the following block diagram and determine the transfer function. H1 + R(s) +_ + G H2 10 Y(s) ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ 4. Multiple Inputs Control systems often have more than one input. For example, there can be the input signal indicating the required value of the controlled variable and also an input or inputs due to disturbances which affect the system.The procedure to obtain the relationship between the inputs and the output for such systems is: 1. 2. 3. 4. Set all inputs except one equal to zero Determine the output signal due to this one non-zero input Repeat the above steps for each of the remaining inputs in turn The total output of the system is the algebraic sum (superposition) of the outputs due to each of the inputs. Example: Find the output Y(s) of the block diagram in the figure below. D(s) R(s) +_ G1(s) + + H(s) Solution: 11 Y(s) G2(s) ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) _______________________________________________________________________________ Exercise: Determine the output Y(s) of the following system. D1(s) R(s) +_ G1(s) + + Y(s) G2(s) H1(s) + + D2(s) 12 H2(s) ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ 5. Transfer Functions with MATLAB A transfer function of a linear time-invariant (LTI) system can be entered into MATLAB using the command tf(num,den) where num and den are row vectors co ntaining, respectively, the coefficients of the numerator and denominator polynomials of the transfer function.For example, the transfer function: G (s) = 3s + 1 s + 3s + 2 2 can be entered into MATLAB by typing the following on the command line: num = [3 1]; den = [1 3 2]; G = tf(num,den) The output on the MATLAB command window would be: Transfer function: 3s+1 ————s^2 + 3 s + 2 Once the various transfer functions have been entered, you can combine them together using arithmetic operations such as addition and multiplication to evaluate the transfer function of a cascaded system. The following table lists the most common systems connections and the corresponding MATLAB commands to implement them.In the following, SYS refers to the transfer function of a system, i. e. SYS = Y(s)/R(s). System MATLAB command Series connection: R(s) Y(s) G1 G2 SYS = G1*G2 or SYS = series(G1,G2) Parallel connection: G1 + R(s) SYS = G1  ± G2 or SYS = parallel(G1, ±G2) Y(s)  ± G2 Negative feedback connection: R(s) Y(s) +_ G(s) SYS = feedback(G,H) H(s) 13 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ R(s) Y(s) +_ G1 G2 H Example: Evaluate the transfer function of the feedback system shown in the figure above using MATLAB where G1(s) = 4, G2(s) = 1/(s+2) and H(s) = 5s.Solution: Type the following in the MATLAB command line: G1 = tf([0 4],[0 1]); G2 = tf([0 1],[1 2]); H = tf([5 0],[0 1]); SYS = feedback(G1*G2,H) This produces the following output on the command window (check this result): Transfer function: 4 ——-21 s + 2 Exercise: Compute the closed-loop transfer function of the following system using MATLAB. R(s) +_ 1 s +1 14 s+2 s+3 Y(s) ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ 6. Time Response Analysis with MATLABAfter entering the transfer function of a LTI system, we can compute and plot the time response of this system due to different input stimuli in MATLAB. In particular, we will consider the step response, the impulse response, the ramp response, and responses to other simple inputs. 6. 1. Step response To plot the unit-step response of the LTI system SYS=tf(num,den) in MATLAB, we use the command step(SYS). We can also enter the row vectors of the numerator and denominator coefficients of the transfer function directly into the step function: step(num,den).Example: Plot the unit-step response of the following system in MATLAB: Y (s) 2s + 10 =2 R (s) s + 5s + 4 Solution: Step Response 2. 5 num = [0 2 10]; den = [1 5 4]; SYS = tf(num,den); step(SYS) Amplitude 2 or directly: step(num,den) 1. 5 1 MATLAB will then produce the following plot on the screen. Confirm this plot yourself. 0. 5 0 0 1 2 3 Time (sec. ) 4 5 For a step input of magnitude other than unity, for example K, simply multiply the transfer function SY S by the constant K by typing step(K*SYS). For example, to plot the response due to a step input of magnitude 5, we type step(5*SYS).Notice in the previous example that that time axis was scaled automatically by MATLAB. You can specify a different time range for evaluating the output response. This is done by first defining the required time range by typing: t = 0:0. 1:10; % Time axis from 0 sec to 10 sec in steps of 0. 1 sec and then introducing this time range in the step function as follows: step(SYS,t) % Plot the step response for the given time range, t This produces the following plot for the same example above. 15 6 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) _______________________________________________________________________________ Step Response 2. 5 Amplitude 2 1. 5 1 0. 5 0 0 2 4 6 8 10 Time (sec. ) You can also use the step function to plot the step responses of multiple LTI systems SYS1, SYS2, †¦ etc. on a single figure in MATLAB by typing: st ep(SYS1,SYS2,†¦ ) 6. 2. Impulse response The unit-impulse response of a control system SYS=tf(num,den) may be plotted in MATLAB using the function impulse(SYS). Example: Plot the unit-impulse response of the following system in MATLAB: Y(s) 5 = R (s) 2s + 10 Solution: Impulse Response um = [0 5]; den = [2 10]; SYS = tf(num,den); impulse(SYS) 2. 5 2 impulse(num,den) Amplitude or directly 1. 5 1 This will produce the following output on the screen. Is that what you would expect? 0. 5 0 0 0. 2 0. 4 0. 6 Time (sec. ) 16 0. 8 1 1. 2 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ 6. 3. Ramp response There is no ramp command in MATLAB. To obtain the unit ramp response of the transfer function G(s): multiply G(s) by 1/s, and use the resulting function in the step command.The step command will further multiply the transfer function by 1/s to make the input 1/s2 i. e. Laplace transform of a un it-ramp input. For example, consider the system: Y(s) 1 =2 R (s) s + s + 1 With a unit-ramp input, R(s) = 1/s2, the output can be written in the form: Y(s) = 1 1 1 R (s) = 2 ? s + s +1 (s + s + 1)s s 2 1 ? ?1 =? 3 2 ?s + s + s ? s which is equivalent to multiplying by 1/s and then working out the step response. To plot the unitramp response of this system, we enter the numerator and denominator coefficients of the term in square brackets into MATLAB: num = [0 0 0 1]; en = [1 1 1 0]; and use the step command: step(num,den) The unit ramp response will be plotted by MATLAB as shown below. Step Response 12 10 Amplitude 8 6 4 2 0 0 2 4 6 Time (sec. ) 17 8 10 12 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ 6. 4. Arbitrary response To obtain the time response of the LTI system SYS=tf(num,den) to an arbitrary input (e. g. exponential function, sinusoidal function .. etc. ), we can use the lsim command (stands for ‘linear simulation') as follows: lsim(SYS,r,t) or lsim(num,den,r,t) here num and den are the row vectors of the numerator and denominator coefficients of the transfer function, r is the input time function, and t is the time range over which r is defined. Example: Use MATLAB to obtain the output time response of the transfer function: Y(s) 2 = R (s) s + 3 when the input r is given by r = e-t. Solution: Start by entering the row vectors of the numerator and denominator coefficients in MATLAB: num = [0 2]; den = [1 3]; Then specify the required time range and define the input function, r, over this time: t = 0:0. 1:6; r = exp(-t); % Time range from 0 to 6 sec in steps of 0. 1 sec Input time function Enter the above information into the lsim function by typing: lsim(num,den,r,t) This would produce the following plot on the screen. Linear Simulation Results 0. 4 0. 35 Amplitude 0. 3 0. 25 0. 2 0. 15 0. 1 0. 05 0 0 1 2 3 Time (sec. ) 18 4 5 6 ECM2105 – C ontrol Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ TUTORIAL PROBLEM SHEET 3 1. Find the transfer function between the input force u(t) and the output displacement y(t) for the system shown below. y(t) b1 u(t) m b2 where b1 and b2 are the frictional coefficients.For b1 = 0. 5 N-s/m, b2 = 1. 5 N-s/m, m = 10 kg and u(t) is a unit-impulse function, what is the response y(t)? Check and plot the response with MATLAB. 2. For the following circuit, find the transfer function between the output voltage across the inductor y(t), and the input voltage u(t). R u(t) L y(t) For R = 1 ? , L = 0. 1 H, and u(t) is a unit-step function, what is the response y(t)? Check and plot the result using MATLAB. 3. Find the transfer function of the electrical circuit shown below. R L u(t) y(t) C For R = 1 ? , L = 0. 5 H, C = 0. 5 F, and a unit step input u(t) with zero initial conditions, compute y(t).Sketch the time function y(t) and pl ot it with MATLAB. 19 ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ 4. In the mechanical system shown in the figure below, m is the mass, k is the spring constant, b is the friction constant, u(t) is the external applied force and y(t) is the corresponding displacement. Find the transfer function of this system. k u(t) m For m = 1 kg, k = 1 kg/s2, b = 0. 5 kg/s, and a step input u(t) = 2 N, compute the response y(t) and plot it with MATLAB. b y(t) 5.Write down the transfer function Y(s)/R(s) of the following block diagram. R(s) Y(s) K +_ G(s) a) For G(s) = 1/(s + 10) and K = 10, determine the closed loop transfer function with MATLAB. b) For K = 1, 5, 10, and 100, plot y(t) on the same window for a unit-step input r(t) with MATLAB, respectively. Comment on the results. c) Repeat (b) with a unit-impulse input r(t). 6. Find the closed loop transfer function for the following diagram. R(s) E(s) Y(s) G(s) +_ F(s) H(s) a) For G(s) = 8/(s2 + 7s + 10) and H(s) = s+2, determine the closed loop transfer function with MATLAB. ) Plot y(t) for a unit-step input r(t) with MATLAB. 7. Determine the transfer function of the following diagram. Check your answer with MATLAB. _ R(s) +_ s s + + 1/s s 20 1/s Y(s) ECM2105 – Control Engineering Dr Mustafa M Aziz (2010) ________________________________________________________________________________ 8. Determine the transfer function of the following diagram. R(s) +_ +_ 50 s +1 Y(s) s 2/s 1/s2 2 +_ a) Check you result with MATLAB. b) Plot y(t) for a unit-impulse input r(t) with MATLAB. 9. Determine the total output Y(s) for the following system. D(s)

Joan Miro and Dutch Interior Essay

Joan Miro created a surrealist painting, a style that expresses the subconscious using imagery in the subject matter, Dutch Interior shows a man playing the guitar at a table. There are animals and a women sitting around him listening to the beautiful sound. Miro used a wide array of colors especially green and white to emphasize a happy day. He uses complementary colors to allow the colors to clash and have things stand out and be unified from the rest of the canvas. Joan Miro created this painting by observing another painting called The Lute Player. He painted, distorted, simplified and abstracted it by drawing only what he thought was important of the object and using the colors he thought best represented the figure. Miro feels that it is not important to show every little detail because doing that gives your imagination no room to imagine. To him abstracting his images is the best way for him to express his inner feelings. In this painting the Dutch Interior he feels the most i mportant thing is the fact that a man is playing a guitar and so he paints that. He does not think the painting was painted to show the mans velvet hat so he leaves that out. Miro puts a happy warm feeling into his work by painting soft but brilliant colors onto his canvas. He puts soft whites into his painting to emphasize that warm mood of joy. Miro uses the color white also to show important areas of the canvas. Miro also uses some principles of design to try to give this feeling. He uses movement to lead your eye around starting from the man playing the guitar and ending in the lower left hand corner at the place where the dog is sitting. The central focus is the man playing the guitar because he is what the whole painting is basically about. One other important principle of design he uses is asymmetrical balance. There are the same amount of things happening on both sides of the musician. On the left you have a dog starring up at him and listening to the comforting music while on the right side the cat is doing the same thing. Although the central focus is the musician things are happening through out the canvas. Such as out the window there are people sailing boats and inside there are many different animals listening. I get the feeling of a happy day and all is going well and there is nice soft music in the background. The day is calm and nothing can go wrong, everything is just perfect. This painting was painted for the one reason to make people warm and happy inside and to tell people every where that detail is not needed in a painting as long as you have your imagination leading you through it. Miro wants to tell you that there is more to art than recognizable subject matter. You don’t have to know what your looking at.

Community Marketing Through Social Media Essay Example | Topics and Well Written Essays - 750 words

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Physiology - Essay Example The reason is that at higher altitudes, there is lesser amount of oxygen for the body and muscles. Therefore, the excess oxygen will help avoid the early production of lactic acid and keep heart rate lower even when the athlete is working harder at sea level. (Smith, 2005) The trick to high altitude training is a process known as acclimatization. This means that athletes must give time to their bodies to get used to the increase in altitude, and decrease in oxygen levels in the atmosphere. For instance, when an athlete reaches, say 5000 feet, he must spend some days there so that the body acclimatizes to the conditions present there before moving on to higher altitudes. After acclimatization to higher altitudes, when the athlete returns back to sea level, his endurance level and performance is better. As the oxygen levels at higher altitudes decrease, there are a number of changes that the body undergoes in the process of acclimatization. Firstly, the depth of respiration increases. The pulmonary arteries go through an increase in pressure, forcing blood into those parts of the lung which are not utilized under normal circumstances. (Curtis, 1999) Along with increasing the production of red blood cells to carry oxygen, the body also steps up the production of a specific enzyme that eases the discharge of oxygen from hemoglobin to the body tissue. (Curtis, 1999) As we know, the air in the atmosphere consists of 78% nitrogen, 21% oxygen and 1% water vapor, carbon dioxide and other gases. This is the proportion of gases you inhale during normal breathing. However, 6% of oxygen is breathed out together with carbon dioxide and other waste products. (Science Fair 2003: Does Exercise Affect the Amount of Carbon Dioxide Exhaled, 2003) During exercise, the body needs more energy which is provided to it through the chemical reaction of oxygen and glucose. This, in turn, means that during exercise, the body needs more

Ratio analysis Coursework Example | Topics and Well Written Essays - 250 words

Ratio analysis - Coursework Example Assets turnover ratio measures the amount of revenue generated from assets owned by the company. A decreasing trend because of reducing sales implies that promotions and advertising of sales must be done (Gibson and Gibson 187). The debt to income ratio measures the level of total income to that of total assets of the company. The company’s increasing ratio of 0.01% means that the both assets and sales are on the rise. Debt to equity ratio increases in the current year which means a lesser risk to the potential shareholders of the company. The investment potential of the company is safer for the likely investors. Competitors in the same industry are competing fairly with the company. The higher the higher the interest cover means improved ability of the company to pay its obligations. The company has enough chance to bear the amount of its prevailing finance cost. From its assets turnover ratio, the company is not optimizing the use of its assets. The company cannot generate more sales with any fewer assets. Decreasing asset turnover ratio means a negative impact on the return on equity (Gibson and Gibson